(C) The given quadratic equation is in the form $ax^{2}+bx+c=0$.Comparing $x^{2}-5x-14=0$ with the standard form,we get $a=1$,$b=-5$,and $c=-14$.The d

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(C) The given quadratic equation is in the form $ax^{2}+bx+c=0$.Comparing $x^{2}-5x-14=0$ with the standard form,we get $a=1$,$b=-5$,and $c=-14$.The discriminant $D$ is given by the formula $D=b^{2}-4ac$.Substituting the values,we get $D=(-5)^{2}-4(1)(-14)$.$D=25+56$.$D=81$.Therefore,the discriminant is $81$.

Class 10 Mathematics Quadratic Equations Mix Examples - Quadratic Equations

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Find the discriminant of the following quadratic equation: $x^{2}-5x-14=0$.

A
$12$
B
$55$
C
$81$
D
$70$

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Mix Examples - Quadratic Equations

Solve the following equation using the method of factorization: $(x+2)^{2}-14(x+2)+45=0$

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Find the discriminant of the following quadratic equation: $x^{2}-5x-14=0$.

Similar Questions

Solve the following equation using the method of factorization: $(x+2)^{2}-14(x+2)+45=0$

Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $x^{2} + x - 3 = 0$

If both the roots of a quadratic equation $kx^{2} + 4x + 1 = 0$ are equal,then $k = \ldots$

If one of the roots of the equation $x^{2} - \sqrt{p}x + q = 0$ where $p, q \in R$ is $x = -\sqrt{p}$,then prove that $2p + q = 0$.

Solve the following equation using the method of factorization and write its solution set: $\frac{x}{x+1} + \frac{x+1}{x} = \frac{41}{20}$

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